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Game Progress
對局進行對局進行
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Try the problems below!
In each case some of the opponents’ stones can be captured with one move.
試試以下問題\!
每道題都是以 一手 提吃對方某些棋子。試試以下問題\!
每道題都是以 一手 提吃對方某些棋子。
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Problems
問題集問題集
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A string of stones is in Atari when it has only one liberty left.
當龍（成串的一方棋子）只剩 一氣 時，將被叫吃。當龍（成串的一方棋子）只剩 一氣 時，將被叫吃。
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The winner is the player who first captures one or more opponent stones.
勝方玩家是首先提吃對方棋子者。勝方玩家是首先提吃對方棋子者。
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Capture Examples
吃子（提子）範例吃子（提子）範例
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In the following are some tips on playing capture-go.
以下是一些進行吃子（提子）遊戲的小技巧。以下是一些進行吃子（提子）遊戲的小技巧。
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Below are some examples of capturing stones. In all cases black A can capture white stones (B).
下方是一些吃子（提子）的範例，在所有的例子中都是黑 A 要提吃 白子（B）。下方是一些吃子（提子）的範例，在所有的例子中都是黑 A 要提吃 白子（B）。
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Capture Go Rules
吃子（提子）規則吃子（提子）規則
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One of the players takes black "stones" and the other player takes white "stones". The board is a grid of 9 by 9 lines.
The game starts with 4 stones are on the board as shown in the diagram.
Black player starts the game. Each player plays a single stone of their own color. A player can play to any empty intersection. A player may not pass. Once the stone is played it is never moved to another intersection.
玩家一方持 黑子，另一方持 白子。棋盤是 9 縱、9 橫的格線交會而成，即 9 路棋盤。
對局開始時如圖面上所示在棋盤上放置 4 子。
對局開始，黑方先下。依次一人一手。玩家可將棋子放置於任一格線交會的空點上。玩家必須待棋子再也沒有可下的空點時，才可以 虚手。玩家一方持 黑子，另一方持 白子。棋盤是 9 縱、9 橫的格線交會而成，即 9 路棋盤。
對局開始時如圖面上所示在棋盤上放置 4 子。
對局開始，黑方先下。依次一人一手。玩家可將棋子放置於任一格線交會的空點上。玩家必須待棋子再也沒有可下的空點時，才可以 虚手。
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Game has two players: You and Hactar.
遊戲有 2 位玩家，你和遊戲有 2 位玩家，你和 Hactar。。
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The player can capture a stone by playing into its last liberty. In the diagram a white stone A is captured when black plays to B. Liberties are empty intersection connected to a stone by line.
玩家下在棋子最後一氣的位置就可以提吃。圖面上，黑下在 B， 白子 A 就被提吃。氣 是指緊鄰在連接成線型棋子旁的 空 格線交叉點。玩家下在棋子最後一氣的位置就可以提吃。圖面上，黑下在 B， 白子 A 就被提吃。氣 是指緊鄰在連接成線型棋子旁的 空 格線交叉點。
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Parsing of the “HactarFull/src/main/res/raw-zh-rCN/rules_atarigo_text.properties” file was enforced. 3 years ago
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If none of the opponent’s stones is in atari, then the player should check if any of his own stones are in atari.
If players stones are in atari, he should try to increase their liberties so that the opponent cannot capture then in his turn.
 
3 years ago
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Try the problems below!
In each case some of the opponents’ stones can be captured with one move.
 
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Parsing of the “HactarFull/src/main/res/raw-tr/rules_atarigo_text.properties” file was enforced. 3 years ago
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A player can capture opponents stones if any of the stones are in atari.
Oyuncu, rakip taşşlar esir alıınabilir durumdaysa, hemen son nefesine oynar.
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If none of the opponent’s stones is in atari, then the player should check if any of his own stones are in atari.
If players stones are in atari, he should try to increase their liberties so that the opponent cannot capture then in his turn.
Rakip taşlarışların hiçç biri esir alıınma durumunda değğilse, oyuncu kendi taşlarınışlarının esir olma durumlarınıını kontrol etmeli.
Eğğer oyuncunun taşlarışları esir alıınabilir durumda ise, oyuncu taşlarınışlarının nefesini arttıırmaya çalışmalıdır böçalışmalıdır böylece rakibine sııra geldiğğinde esir alma durumu ortadan kalkar.
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A string of stones is captured by playing into string's last liberty. In the diagram white stones (A) are captured when black plays into B. A stone string consists all the stones connected by lines. A string does not connect diagonally.
Birbirine bağlı taşğlı taşlar, son nefesleri kapatıılarak esir alınır. Şınır. Şekilde beyaz taşşlar(A) siyahıın B noktasıına oynamasııyla esir alınıınır. Bir ççizgi üüzerinde(yatay-dikey) dizilen taşşlar bağlı taşğlı taşlardıır.Taşşlar ççapraz olarak bağğlanamaz.
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Tips
Ä°İpucu
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